The following concentrations were observed at 500 K for the formation of NH_3 from N_2 and H_2. At equilibrium; [ N_2]=2 × 10^-2 M,[ H_2]=3 × 10^-2 M…

The following concentrations were observed at $\displaystyle 500$ K for the formation of $\displaystyle \mathrm{NH}_3$ from $\displaystyle \mathrm{N}_2$ and $\displaystyle \mathrm{H}_2$. At equilibrium ; $\displaystyle \left[\mathrm{N}_2\right]=2 \times 10^{-2} \mathrm{M},\left[\mathrm{H}_2\right]=3 \times 10^{-2} \mathrm{M}$ and $\displaystyle \left[\mathrm{NH}_3\right]=1.5 \times 10^{-2} \mathrm{M}$. Equilibrium constant for the reaction is $\displaystyle \_\_\_\_$.