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Chemistry · 2021

JEE Main · 27 August 2021, Shift 2 · Q59

The first order rate constant for the decomposition of CaCO_3 at 700 K is 6.36 × 10^-3 s^-1 and activation energy is 209 kJ mol^-1. Its rate constant…

The first order rate constant for the decomposition of $\displaystyle \mathrm{CaCO}_3$ at $\displaystyle 700$ K is $\displaystyle 6.36 \times 10^{-3} \mathrm{~s}^{-1}$ and activation energy is $\displaystyle 209 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Its rate constant (in $\displaystyle \mathrm{s}^{-1}$) at $\displaystyle 600$ K is $\displaystyle x \times 10^{-6}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest integer) [Given $\displaystyle \mathrm{R}=8.31 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19,10^{-4.79}=1.62 \times 10^{-5}$ ]
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