Chemistry · 2022
JEE Main · 29 June 2022, Shift 2 · Q85
The equation k =(6.5 × 10^12 s^-1) e^-26000 K / T is followed for the decomposition of compound A. The activation energy for the reaction is \ \ \ \…
The equation
$$\mathrm{k}=\left(6.5 \times 10^{12} \mathrm{~s}^{-1}\right) \mathrm{e}^{-26000 \mathrm{~K} / \mathrm{T}}
$$
is followed for the decomposition of compound A . The activation energy for the reaction is \_\_\_\_ $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$. [nearest integer]
(Given: $\displaystyle \mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )
Official answer
216
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.