Chemistry · 2022
JEE Main · 27 July 2022, Shift 2 · Q61
The correct decreasing order of energy for the orbitals having, following set of quantum numbers: (A) n =3, l =0, m =0 (B) n =4, l =0, m =0 (C) n =3,…
The correct decreasing order of energy for the orbitals having, following set of quantum numbers :
(A)
$\displaystyle \mathrm{n}=3, \mathrm{l}=0, \mathrm{~m}=0$
(B)
$\displaystyle \mathrm{n}=4, \mathrm{l}=0, \mathrm{~m}=0$
(C)
$\displaystyle \mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}=0$
(D)
$\displaystyle \mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}=1$
Official answer
(1)
$\displaystyle (\mathrm{D})>(\mathrm{B})>(\mathrm{C})>(\mathrm{A})$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.