Production of iron in blast furnace follows the following equation Fe_3 O_4( s )+4 CO ( g ) → 3 Fe ( l )+4 CO_2( g ) when 4.640 kg of Fe_3 O_4 and…

Production of iron in blast furnace follows the following equation $$\mathrm{Fe}_3 \mathrm{O}_4(\mathrm{~s})+4 \mathrm{CO}(\mathrm{~g}) \rightarrow 3 \mathrm{Fe}(\mathrm{l})+4 \mathrm{CO}_2(\mathrm{~g}) $$ when $\displaystyle 4.640$ kg of $\displaystyle \mathrm{Fe}_3 \mathrm{O}_4$ and $\displaystyle 2.520$ kg of CO are allowed to react then the amount of iron (in g) produced is : [Given: Molar Atomic mass $\displaystyle \left(\mathrm{g} \mathrm{mol}^{-1}\right): \mathrm{Fe}=56$ Molar Atomic mass $\displaystyle \left(\mathrm{g} \mathrm{mol}^{-1}\right): \mathrm{O}=16$ Molar Atomic mass $\displaystyle \left.\left(\mathrm{g} \mathrm{mol}^{-1}\right): \mathrm{C}=12\right]$