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Chemistry · 2020

JEE Main · 3 September 2020, Shift 2 · Q46

6.023 × 10^22 molecules are present in 10 g of a substance ^′ x^′. The molarity of a solution containing 5 g of substance ^′ x^′ in 2 L solution is \…

$\displaystyle 6.023 \times 10^{22}$ molecules are present in $\displaystyle 10$ g of a substance $\displaystyle { }^{\prime} x^{\prime}$. The molarity of a solution containing $\displaystyle 5$ g of substance $\displaystyle { }^{\prime} x^{\prime}$ in $\displaystyle 2$ L solution is \_\_\_\_ $\displaystyle \times 10^{-3}$.
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.