SolveIt is under development
SolveItJEE Main
Chemistry · 2019

JEE Main · 9 April 2019, Shift 1 · Q56

Liquid ' M ' and liquid ' N ' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 mmHg, respectively, at the…

Liquid ' M ' and liquid ' N ' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are $\displaystyle 450$ and $\displaystyle 700$ mmHg, respectively, at the same temperature. Then correct statement is : $$\begin{aligned} & \left(x_{\mathrm{M}}=\text { Mole fraction of ' } \mathrm{M}\right. \text { ' in solution; } \\ & x_{\mathrm{N}}=\text { Mole fraction of ' } \mathrm{N} \text { ' in solution; } \\ & y_{\mathrm{M}}=\text { Mole fraction of ' } \mathrm{M} \text { ' in vapour phase; } \\ & \left.y_{\mathrm{N}}=\text { Mole fraction of ' } \mathrm{N} \text { ' in vapour phase }\right) \end{aligned} $$
ShareWhatsAppTelegram

More from Solutions

JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.