Chemistry · 2019
JEE Main · 9 April 2019, Shift 1 · Q56
Liquid ' M ' and liquid ' N ' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 mmHg, respectively, at the…
Liquid ' M ' and liquid ' N ' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are $\displaystyle 450$ and $\displaystyle 700$ mmHg, respectively, at the same temperature. Then correct statement is :
$$\begin{aligned}
& \left(x_{\mathrm{M}}=\text { Mole fraction of ' } \mathrm{M}\right. \text { ' in solution; } \\
& x_{\mathrm{N}}=\text { Mole fraction of ' } \mathrm{N} \text { ' in solution; } \\
& y_{\mathrm{M}}=\text { Mole fraction of ' } \mathrm{M} \text { ' in vapour phase; } \\
& \left.y_{\mathrm{N}}=\text { Mole fraction of ' } \mathrm{N} \text { ' in vapour phase }\right)
\end{aligned}
$$
Official answer
(2)
$\displaystyle \frac{x_{\mathrm{M}}}{x_{\mathrm{N}}}>\frac{y_{\mathrm{M}}}{y_{\mathrm{N}}}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.