In sulphur estimation, 2.0 × 10^-3 mol of an organic compound ( X ) (molar mass 76 g mol^-1 ) gave 0.4813 g of barium sulphate (molar mass 233 g…

In sulphur estimation, $\displaystyle 2.0 \times 10^{-3} \mathrm{~mol}$ of an organic compound $\displaystyle (\mathrm{X})$ (molar mass $\displaystyle 76 \mathrm{~g} \mathrm{~mol}^{-1}$ ) gave $\displaystyle 0.4813$ g of barium sulphate (molar mass $\displaystyle 233 \mathrm{~g} \mathrm{~mol}^{-1}$ ). The percentage of sulphur in the compound $\displaystyle (\mathrm{X})$ is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-1} \%$ (Nearest integer)