0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound ( X ) is 26.7 %. Total…

$\displaystyle 0$ g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave $\displaystyle 3.36$ g of AgBr . The percentage of carbon in the compound $\displaystyle (\mathrm{X})$ is $\displaystyle 26.7 \%$. Total number of carbon atoms in the empirical formula for compound $\displaystyle (\mathrm{X})$ is $\displaystyle \_\_\_\_$. (Given molar mass in $\displaystyle \mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{Br}: 80, \mathrm{Ag}: 108$ )