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Chemistry · 2026

JEE Main · 21 January 2026, Shift 1 · Q62

In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol^-1 ). Molar mass of…

In Carius method, $\displaystyle 0.75$ g of an organic compound gave $\displaystyle 1.2$ g of barium sulphate, find percentage of sulphur (molar mass $\displaystyle 32 \mathrm{~g} \mathrm{~mol}^{-1}$ ). Molar mass of barium sulphate is $\displaystyle 233 \mathrm{~g} \mathrm{~mol}^{-1}$.
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.