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Chemistry · 2021

JEE Main · 22 July 2021, Shift 2 · Q51

If the concentration of glucose ( C_6 H_12 O_6) in blood is 0.72 g L^-1, the molarity of glucose in blood is \ \ \ \ × 10^-3 M. (Nearest integer)…

If the concentration of glucose $\displaystyle \left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)$ in blood is $\displaystyle 0.72 \mathrm{~g} \mathrm{~L}^{-1}$, the molarity of glucose in blood is \_\_\_\_ $\displaystyle \times 10^{-3} \mathrm{M}$. (Nearest integer) (Given : Atomic mass of $\displaystyle \mathrm{C}=12, \mathrm{H}=1, \mathrm{O}=16 \mathrm{u}$ )
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.