Chemistry · 2019
JEE Main · 11 January 2019, Shift 1 · Q59
If a reaction follows the Arrhenius equation, the plot lnk vs 1/(( RT )) gives straight line with a gradient (-y) unit. The energy required to…
If a reaction follows the Arrhenius equation, the plot lnk vs $\displaystyle \frac{1}{(\mathrm{RT})}$ gives straight line with a gradient $\displaystyle (-y)$ unit. The energy required to activate the reactant is :
Official answer
(2)
$\displaystyle y$ unit
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.