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Chemistry · 2014

JEE Main · 11 April 2014, Shift 1 · Q37

Given Fe^3+( aq )+ e^- → Fe^2+( aq ); E^°=+0.77 V; Al^3+( aq )+3 e^- → Al ( s ); E^°=-1.66 V; Br_2( aq )+2 e^- → 2 Br^-; E^°=+1.09 V Considering the…

Given $$\begin{aligned} & \mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+}(\mathrm{aq}) ; \mathrm{E}^{\circ}=+0.77 \mathrm{~V} \\ & \mathrm{Al}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Al}(\mathrm{~s}) ; \mathrm{E}^{\circ}=-1.66 \mathrm{~V} \\ & \mathrm{Br}_2(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Br}^{-} ; \mathrm{E}^{\circ}=+1.09 \mathrm{~V} \end{aligned} $$ Considering the electrode potentials, which of the following represents the correct order of reducing power ?
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JEE Main 2014 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.