Chemistry · 2020
JEE Main · 7 January 2020, Shift 2 · Q26
For the reaction 2 H_2( g )+2 NO ( g ) → N_2( g )+2 H_2 O ( g ) the observed rate expression is, rate = k_f [ NO ]^2[ H_2]. The rate expression for…
For the reaction
$$2 \mathrm{H}_2(\mathrm{~g})+2 \mathrm{NO}(\mathrm{~g}) \rightarrow \mathrm{N}_2(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{~g})
$$
the observed rate expression is, rate $\displaystyle =\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^2\left[\mathrm{H}_2\right]$. The rate expression for the reverse reaction is :
Official answer
(4)
$\displaystyle \mathrm{k}_{\mathrm{b}}\left[\mathrm{~N}_2\right]\left[\mathrm{H}_2 \mathrm{O}\right]^2 /\left[\mathrm{H}_2\right]$
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.