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Chemistry · 2020

JEE Main · 8 January 2020, Shift 1 · Q30

For the Balmer series in the spectrum of H atom, ν̄= R_H {1/(n_1^2)-1/(n_2^2)}, the correct statements among (I) to (IV) are: (I) As wavelength…

For the Balmer series in the spectrum of H atom, $\displaystyle \bar{\nu}=\mathrm{R}_{\mathrm{H}}\left\{\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right\}$, the correct statements among (I) to (IV) are :
(I)
As wavelength decreases, the lines in the series converge
(II)
The integer $\displaystyle \mathrm{n}_1$ is equal to $\displaystyle 2$
(III)
The lines of longest wavelength corresponds to $\displaystyle \mathrm{n}_2=3$
(IV)
The ionization energy of hydrogen can be calculated from wave number of these lines
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.