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Chemistry · 2026

JEE Main · 2 April 2026, Shift 1 · Q74

For reaction A → P, rate constant k =1.5 × 10^3 s^-1 at 27^° C If activation energy for the above reaction is 60 kJ mol^-1, then the temperature (in…

For reaction $\displaystyle \mathrm{A} \rightarrow \mathrm{P}$, rate constant $\displaystyle \mathrm{k}=1.5 \times 10^3 \mathrm{~s}^{-1}$ at $\displaystyle 27^{\circ} \mathrm{C}$ If activation energy for the above reaction is $\displaystyle 60 \mathrm{~kJ} \mathrm{~mol}^{-1}$, then the temperature (in $\displaystyle { }^{\circ} \mathrm{C}$ ) at which rate constant, $\displaystyle \mathrm{k}=4.5 \times 10^3 \mathrm{~s}^{-1}$ is $\displaystyle \_\_\_\_$. (Nearest integer) Given : $\displaystyle \log 2=0.30, \log 3=0.48, \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \ln 10=2.3$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.