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Chemistry · 2019
JEE Main · 9 January 2019, Shift 1 · Q53
For emission line of atomic hydrogen from n_i =8 to n_f = n, the plot of wave number (v̄) against (1/(n^2)) will be (The Rydberg constant, R_H is in…
For emission line of atomic hydrogen from $\displaystyle \mathrm{n}_{\mathrm{i}}=8$ to $\displaystyle \mathrm{n}_{\mathrm{f}}=\mathrm{n}$, the plot of wave number $\displaystyle (\bar{v})$
against $\displaystyle \left(\frac{1}{\mathrm{n}^2}\right)$ will be (The Rydberg constant, $\displaystyle \mathrm{R}_{\mathrm{H}}$ is in wave number unit)
Official answer
(2)
Linear with slope $\displaystyle -\mathrm{R}_{\mathrm{H}}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.