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Chemistry · 2022

JEE Main · 28 July 2022, Shift 2 · Q58

For a reaction, given below is the graph of ln k vs 1/T. The activation energy for the reaction is equal to \ \ \ \ cal mol^-1. (nearest integer)…

For a reaction, given below is the graph of $\displaystyle \ln \mathrm{k}$ vs $\displaystyle \frac{1}{\mathrm{~T}}$. The activation energy for the reaction is equal to \_\_\_\_ cal $\displaystyle \mathrm{mol}^{-1}$. (nearest integer) (Given : $\displaystyle \mathrm{R}=2 \mathrm{cal} \mathrm{K}^{-1} \mathrm{~mol}^{-1}$ ) Figure: JEE Main Chemistry 2022, Chemical Kinetics
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.