Chemistry · 2019
JEE Main · 9 April 2019, Shift 1 · Q51
For a reaction, N_2( g )+3 H_2( g ) → 2 NH_3( g ); identify dihydrogen ( H_2) as a limiting reagent in the following reaction mixtures.
For a reaction,
$$\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_3(\mathrm{~g}) ; \text { identify }
$$
dihydrogen $\displaystyle \left(\mathrm{H}_2\right)$ as a limiting reagent in the following reaction mixtures.
Official answer
(4)
$\displaystyle 56 \mathrm{~g} \text { of } \mathrm{N}_2+10 \mathrm{~g} \text { of } \mathrm{H}_2$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.