Chemistry · 2019
JEE Main · 12 January 2019, Shift 2 · Q59
For a reaction, consider the plot of ln k versus 1/T given in the figure. If the rate constant of this reaction at 400 K is 10^-5 s^-1, then the rate…
For a reaction, consider the plot of $\displaystyle \ln \mathrm{k}$ versus $\displaystyle 1$/T given in the figure. If the rate constant of this reaction at $\displaystyle 400$ K is $\displaystyle 10^{-5} \mathrm{~s}^{-1}$, then the rate constant at $\displaystyle 500$ K is :
Official answer
(1)
$\displaystyle 10^{-4} \mathrm{~s}^{-1}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.