SolveIt is under development
SolveItJEE Main
Question 116 / 166 · latest first
Chemistry · 2022

JEE Main · 28 June 2022, Shift 1 · Q88

For a first order reaction A → B, the rate constant, k =5.5 × 10^-14 s^-1. The time required for 67 % completion of reaction is x × 10^-1 times the…

For a first order reaction $\displaystyle \mathrm{A} \rightarrow \mathrm{B}$, the rate constant, $\displaystyle \mathrm{k}=5.5 \times 10^{-14} \mathrm{~s}^{-1}$. The time required for $\displaystyle 67 \%$ completion of reaction is $\displaystyle x \times 10^{-1}$ times the half life of reaction. The value of $\displaystyle x$ is \_\_\_\_ (Nearest integer) (Given : $\displaystyle \log 3=0.4771$ )
ShareWhatsAppTelegram

More from Chemical Kinetics

JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.