Chemistry · 2018
JEE Main · 15 April 2018, Shift 2 · Q40
For a first order reaction, A → P, t_1 / 2 (halflife) is 10 days. The time required for 1/4^th conversion of A (in days) is: ( ln 2=0.693, ln 3=1.1)
For a first order reaction, $\displaystyle \mathrm{A} \rightarrow \mathrm{P}, \mathrm{t}_{1 / 2}$ (halflife) is $\displaystyle 10$ days. The time required for $\displaystyle \frac{1}{4}^{\text {th }}$ conversion of A (in days) is :
$\displaystyle (\ln 2=0.693, \ln 3=1.1)$
Official answer
(3)
$\displaystyle 4.1$
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