SolveIt is under development
SolveItJEE Main
Chemistry · 2018

JEE Main · 15 April 2018, Shift 2 · Q40

For a first order reaction, A → P, t_1 / 2 (halflife) is 10 days. The time required for 1/4^th conversion of A (in days) is: ( ln 2=0.693, ln 3=1.1)

For a first order reaction, $\displaystyle \mathrm{A} \rightarrow \mathrm{P}, \mathrm{t}_{1 / 2}$ (halflife) is $\displaystyle 10$ days. The time required for $\displaystyle \frac{1}{4}^{\text {th }}$ conversion of A (in days) is : $\displaystyle (\ln 2=0.693, \ln 3=1.1)$
ShareWhatsAppTelegram

More from Chemical Kinetics

JEE Main 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.