SolveIt is under development
SolveItJEE Main
Question 143 / 166 · latest first
Chemistry · 2021

JEE Main · 17 March 2021, Shift 1 · Q58

For a certain first order reaction 32 % of the reactant is left after 570 s. The rate constant of this reaction is \ \ \ \ × 10^-3 s^-1. (Round off…

For a certain first order reaction $\displaystyle 32 \%$ of the reactant is left after $\displaystyle 570$ s . The rate constant of this reaction is \_\_\_\_$\displaystyle \times 10^{-3} \mathrm{~s}^{-1}$. (Round off to the Nearest Integer). [Given : $\displaystyle \log _{10} 2=0.301, \ln 10=2.303$ ]
ShareWhatsAppTelegram

More from Chemical Kinetics

JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.