During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is ____ %.…

During "S" estimation, $\displaystyle 160$ mg of an organic compound gives $\displaystyle 466$ mg of barium sulphate. The percentage of Sulphur in the given compound is $\displaystyle \_\_\_\_$ %. (Given molar mass in $\displaystyle \mathrm{g} \mathrm{mol}^{-1}$ of $\displaystyle \mathrm{Ba}: 137, \mathrm{~S}: 32, \mathrm{O}: 16$ )