In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ____ ×…

In the sulphur estimation, $\displaystyle 0.20$ g of a pure organic compound gave $\displaystyle 0.40$ g of barium sulphate. The percentage of sulphur in the compound is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-1} \%$. (Molar mass : $\displaystyle \mathrm{O}=16, \mathrm{~S}=32, \mathrm{Ba}=137$ in $\displaystyle \mathrm{g} \mathrm{mol}^{-1}$ )