Chemistry · 2024
JEE Main · 5 April 2024, Shift 2 · Q84
Considering acetic acid dissociates in water, its dissociation constant is 6.25 × 10^-5. If 5 mL of acetic acid is dissolved in 1 litre water, the…
Considering acetic acid dissociates in water, its dissociation constant is $\displaystyle 6.25 \times 10^{-5}$. If $\displaystyle 5$ mL of acetic acid is dissolved in $\displaystyle 1$ litre water, the solution will freeze at $\displaystyle -x \times 10^{-2}{ }^{\circ} \mathrm{C}$, provided pure water freezes at $\displaystyle 0{ }^{\circ} \mathrm{C}$.
$\displaystyle x=$ $\displaystyle \_\_\_\_$. (Nearest integer)
Given: $\displaystyle \left(\mathrm{K}_f\right)_{\text {water }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$.
density of acetic acid is $\displaystyle 1.2 \mathrm{~g} \mathrm{~mol}^{-1}$.
molar mass of water $\displaystyle =18 \mathrm{~g} \mathrm{~mol}^{-1}$.
molar mass of acetic acid $\displaystyle =60 \mathrm{~g} \mathrm{~mol}^{-1}$.
density of water $\displaystyle =1 \mathrm{~g} \mathrm{~cm}^{-3}$
Acetic acid dissociates as $\displaystyle \mathrm{CH}_3 \mathrm{COOH} \rightleftharpoons \mathrm{CH}_3 \mathrm{COO}^{\ominus}+\mathrm{H}^{\oplus}$
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.