Consider the reaction 4 HNO_3( l )+3 KCl ( s ) → Cl_2( g )+ NOCl ( g )+2 H_2 O ( g )+3 KNO_3( s ) The amount of HNO_3 required to produce 110.0 g of…

Consider the reaction $$4 \mathrm{HNO}_3(\mathrm{l})+3 \mathrm{KCl}(\mathrm{~s}) \rightarrow \mathrm{Cl}_2(\mathrm{~g})+\mathrm{NOCl}(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{~g})+3 \mathrm{KNO}_3(\mathrm{~s}) $$ The amount of $\displaystyle \mathrm{HNO}_3$ required to produce $\displaystyle 110.0$ g of $\displaystyle \mathrm{KNO}_3$ is (Given: Atomic masses of H, O, N and K are $\displaystyle 1$, $\displaystyle 16$, $\displaystyle 14$ and $\displaystyle 39$, respectively.)