SolveIt is under development
SolveItJEE Main
Question 119 / 166 · latest first
Chemistry · 2022

JEE Main · 26 June 2022, Shift 2 · Q88

Catalyst A reduces the activation energy for a reaction by 10 kJ mol^-1 at 300 K. The ratio of rate constants, (k_T, Catalysed)/(k_T, Uncatalysed) is…

Catalyst A reduces the activation energy for a reaction by $\displaystyle 10 \mathrm{~kJ} \mathrm{~mol}^{-1}$ at $\displaystyle 300$ K . The ratio of rate constants, $\displaystyle \frac{\mathrm{k}_{\mathrm{T}} \text {, Catalysed }}{\mathrm{k}_{\mathrm{T}}, \text { Uncatalysed }}$ is $\displaystyle \mathrm{e}^x$. The value of $\displaystyle x$ is \_\_\_\_. [nearest integer] [Assume that the pre-exponential factor is same in both the cases. Given $\displaystyle \mathrm{R}=8.31 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]
ShareWhatsAppTelegram

More from Chemical Kinetics

JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.