Blister copper is produced by reaction of copper oxide with copper sulphide. 2 Cu_2 O + Cu_2 S → 6 Cu + SO_2 When 2.86 × 10^3 g of Cu_2 O and 4.77 ×…

Blister copper is produced by reaction of copper oxide with copper sulphide. $$2 \mathrm{Cu}_2 \mathrm{O}+\mathrm{Cu}_2 \mathrm{~S} \rightarrow 6 \mathrm{Cu}+\mathrm{SO}_2 $$When $\displaystyle 2.86 \times 10^3 \mathrm{~g}$ of $\displaystyle \mathrm{Cu}_2 \mathrm{O}$ and $\displaystyle 4.77 \times 10^3 \mathrm{~g}$ of $\displaystyle \mathrm{Cu}_2 \mathrm{~S}$ are used for reaction, the mass of copper produced is \_\_\_\_ g. (nearest integer) (Atomic mass of $\displaystyle \mathrm{Cu}=63.5$ a.m. u $$\begin{aligned} & \mathrm{S}=32.0 \mathrm{a.m.u} \\ & \mathrm{O}=16.0 \mathrm{a.m.u}) \end{aligned} $$