At what pH, given half cell MnO_4^-(0.1 M ) ∣ Mn^2+(0.001 M ) will have electrode potential of 1.282 V? ____ (Nearest Integer) Given E_MnO_4^- /…

At what pH , given half cell $\displaystyle \mathrm{MnO}_4^{-}(0.1 \mathrm{M}) \mid \mathrm{Mn}^{2+}(0.001 \mathrm{M})$ will have electrode potential of $\displaystyle 1.282$ V? $\displaystyle \_\_\_\_$ (Nearest Integer)Given $\displaystyle \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^{\circ}=1.54 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}$