Chemistry · 2023
JEE Main · 13 April 2023, Shift 2 · Q86
At 298 K, the standard reduction potential for Cu^2+ / Cu electrode is 0.34 V. Given: K_sp Cu ( OH )_2=1 × 10^-20 Take (2.303 RT)/F=0.059 V The…
At $\displaystyle 298$ K , the standard reduction potential for $\displaystyle \mathrm{Cu}^{2+} / \mathrm{Cu}$ electrode is $\displaystyle 0.34$ V .
Given : $\displaystyle \mathrm{K}_{\mathrm{sp}} \mathrm{Cu}(\mathrm{OH})_2=1 \times 10^{-20}$
$$\text { Take } \frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.059 \mathrm{~V}
$$
The reduction potential at $\displaystyle \mathrm{pH}=14$ for the above couple is $\displaystyle (-) x \times 10^{-2} \mathrm{~V}$.
The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$
Official answer
From NTA’s final answer key for this paper.
25
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.