At 27 °C in presence of a catalyst, activation energy of a reaction is lowered by 10 kJ mol^-1. The logarithm of ratio of (k (catalysed))/(k…

At $\displaystyle 27$ °C in presence of a catalyst, activation energy of a reaction is lowered by $\displaystyle 10 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The logarithm of ratio of $\displaystyle \frac{\mathrm{k} \text { (catalysed) }}{\mathrm{k} \text { (uncatalysed) }}$ is.... (Consider that the frequency factor for both the reactions is same)