An organic compound undergoes first order decomposition. The time taken for decomposition to (1/8)^th and (1/10)^th of its initial concentration are…

An organic compound undergoes first order decomposition. The time taken for decomposition to $\displaystyle \left(\frac{1}{8}\right)^{\text {th }}$ and $\displaystyle \left(\frac{1}{10}\right)^{\text {th }}$ of its initial concentration are $\displaystyle \mathrm{t}_{1 / 8}$ and $\displaystyle \mathrm{t}_{1 / 10}$ respectively.What is the value of $\displaystyle \frac{\mathrm{t}_{1 / 8}}{\mathrm{t}_{1 / 10}} \times 10$ ? $\displaystyle (\log 2=0.3)$