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Chemistry · 2019

JEE Main · 10 January 2019, Shift 1 · Q51

A mixture of 100 m mol of Ca ( OH )_2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium…

A mixture of $\displaystyle 100$ m mol of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2$ and $\displaystyle 2$ g of sodium sulphate was dissolved in water and the volume was made up to $\displaystyle 100$ mL . The mass of calcium sulphate formed and the concentration of $\displaystyle \mathrm{OH}^{-}$in resulting solution, respectively, are : (Molar mass of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2, \mathrm{Na}_2 \mathrm{SO}_4$ and $\displaystyle \mathrm{CaSO}_4$ are $\displaystyle 74$, $\displaystyle 143$ and $\displaystyle 136 \mathrm{~g} \mathrm{~mol}^{-1}$, respectively ; $\displaystyle \mathrm{K}_{\mathrm{sp}}$ of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2$ is $\displaystyle 5.5 \times 10^{-6}$ )
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.