A hydrocarbon 'P' ( C_4 H_8) on reaction with HCl gives an optically active compound ' Q ' ( C_4 H_9 Cl ) which on reaction with one mole of ammonia…

A hydrocarbon 'P' $\displaystyle \left(\mathrm{C}_4 \mathrm{H}_8\right)$ on reaction with HCl gives an optically active compound ' $\displaystyle Q$ ' $\displaystyle \left(\mathrm{C}_4 \mathrm{H}_9 \mathrm{Cl}\right)$ which on reaction with one mole of ammonia gives compound ' R ' $\displaystyle \left(\mathrm{C}_4 \mathrm{H}_{11} \mathrm{~N}\right)$. ' R ' on diazotization followed by hydrolysis gives 'S'. Identify P, Q, R and S.