SolveIt is under development
SolveItJEE Main
Chemistry · 2019

JEE Main · 10 April 2019, Shift 1 · Q59

A bacterial infection in an internal wound grows as N^′( t )= N_0 exp ( t ), where the time t is in hours. A dose of antibiotic, taken orally, needs…

A bacterial infection in an internal wound grows as $\displaystyle \mathrm{N}^{\prime}(\mathrm{t})=\mathrm{N}_0 \exp (\mathrm{t})$, where the time t is in hours. A dose of antibiotic, taken orally, needs $\displaystyle 1$ hour to reach the wound. Once it reaches there, the bacterial population goes down as $\displaystyle \frac{d N}{d t}=-5 N^2$. What will be the plot of $\displaystyle \frac{\mathrm{N}_0}{\mathrm{~N}}$ vs. t after $\displaystyle 1$ hour ?
ShareWhatsAppTelegram

More from Chemical Kinetics

JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.