Chemistry · 2019
JEE Main · 11 January 2019, Shift 1 · Q51
A 10 mg effervescent tablet containing sodium bicarbonate and oxalic acid releases 0.25 ml of CO_2 at T =298.15 K and p =1 bar. If molar volume of…
A $\displaystyle 10$ mg effervescent tablet containing sodium bicarbonate and oxalic acid releases $\displaystyle 0.25$ ml of $\displaystyle \mathrm{CO}_2$ at $\displaystyle \mathrm{T}=298.15 \mathrm{~K}$ and $\displaystyle \mathrm{p}=1$ bar. If molar volume of $\displaystyle \mathrm{CO}_2$ is $\displaystyle 25.0$ L under such condition, what is the percentage of sodium bicarbonate in each tablet?
[ Molar mass of $\displaystyle \mathrm{NaHCO}_3=84 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
Official answer
(1)
$\displaystyle 8.4$
More from Some Basic Concepts of Chemistry
- If a rocket runs on a fuel (C_15 H_30) and liquid oxygen, the weight of oxygen required and CO_2 released for every litre of fuel respectively are:…2022
- 2 SO_2( g)+O_2( g) → 2 SO_3( g) The above reaction is carried out in a vessel starting with partial pressures P_SO_2=250 m bar, P_O_2=750 m bar and…2021
- 2.8 × 10^-3 mol of CO_2 is left after removing 10^21 molecules from its ' x ' mg sample. The mass of CO_2 taken initially is Given: N_A=6.02 × 10^23…2025
- The number of molecules and moles in 2.8375 litres of O_2 at STP are respectively2023
- For the given reaction; CaCO_3+2 HCl → CaCl_2+H_2 O+CO_2 If 90 g CaCO_3 is added to 300 mL of HCl which contains 38.55 % HCl by mass and has density…2026
- 10 mL of 2 M NaOH solution is added to 20 mL of 1 M HCl solution kept in a beaker. Now, 10 mL of this mixture is poured into a volumetric flask of…2025
- In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is ____ g. (Nearest…2024
- A chloro compound " A ". (i) forms aldehydes on ozonolysis followed by the hydrolysis. (ii) when vaporized completely 1.53 g of A, gives 448 mL of…2021
JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.