SolveIt is under development
SolveItJEE Main
Question 117 / 195 · latest first
Chemistry · 2022

JEE Main · 29 July 2022, Shift 2 · Q83

80 g of solute A was dissolved in 62.5 cm^3 of ethanol and freezing point of the solution was found to be 155.1 K. The molar mass of solute A is \ \…

$\displaystyle 80$ g of solute $\displaystyle A$ was dissolved in $\displaystyle 62.5 \mathrm{~cm}^3$ of ethanol and freezing point of the solution was found to be $\displaystyle 155.1$ K . The molar mass of solute $\displaystyle A$ is \_\_\_\_ $\displaystyle \mathrm{g} \mathrm{mol}^{-1}$. [Given: Freezing point of ethanol is $\displaystyle 156.0$ K. Density of ethanol is $\displaystyle 0.80 \mathrm{~g} \mathrm{~cm}^{-3}$. Freezing point depression constant of ethanol is $\displaystyle 2.00 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ ]
ShareWhatsAppTelegram

More from Solutions

JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.