Chemistry · 2019
JEE Main · 12 January 2019, Shift 1 · Q51
50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide…
$\displaystyle 50$ mL of $\displaystyle 0.5$ M oxalic acid is needed to neutralize $\displaystyle 25$ mL of sodium hydroxide solution. The amount of NaOH in $\displaystyle 50$ mL of the given sodium hydroxide solution is :
Official answer
No correct option: NTA dropped this question in its final answer key.
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.