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Chemistry · 2021

JEE Main · 24 February 2021, Shift 1 · Q51

5 g of compound A ( MW =90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10^-1. The value of x is \ \ \…

$\displaystyle 5$ g of compound $\displaystyle \mathrm{A}(\mathrm{MW}=90)$ was used to make $\displaystyle 250$ mL of its aqueous solution. The molarity of the solution in M is $\displaystyle x \times 10^{-1}$. The value of $\displaystyle x$ is \_\_\_\_. (Rounded off to the nearest integer)
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.