5 g of a non-volatile, non-electrolyte is dissolved in 100 g of water at 25^° C. The solution showed a boiling point elevation by 2°C. Assuming the…

$\displaystyle 5$ g of a non-volatile, non-electrolyte is dissolved in $\displaystyle 100$ g of water at $\displaystyle 25^{\circ} \mathrm{C}$. The solution showed a boiling point elevation by $\displaystyle 2$°C. Assuming the solute concentration is negligible with respect to the solvent concentration, the vapor pressure of the resulting aqueous solution is $\displaystyle \_\_\_\_$ mm of Hg (nearest integer) [Given: Molal boiling point elevation constant of water $\displaystyle \left(\mathrm{K}_{\mathrm{b}}\right)=0.52 \mathrm{~K} . \mathrm{kg} \mathrm{mol}^{-1}$, $\displaystyle 1$ atm pressure $\displaystyle =760 \mathrm{~mm}$ of Hg , molar mass of water $\displaystyle =18 \mathrm{~g} \mathrm{~mol}^{-1}$ ]