46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of 2.42 × 10^-3 bar. The molar mass of the biopolymer is \ \ \…

$\displaystyle 46$ g of a biopolymer dissolved in a $\displaystyle 100$ mL water at $\displaystyle 300$ K exerted an osmotic pressure of $\displaystyle 2.42 \times 10^{-3}$ bar.The molar mass of the biopolymer is \_\_\_\_ $\displaystyle \times 10^4 \mathrm{~g} \mathrm{~mol}^{-1}$. (Round off to the Nearest Integer) $\displaystyle \left[\right.$ Use $\displaystyle : \mathrm{R}=0.083 \mathrm{~L}$ bar $\displaystyle \left.\mathrm{mol}^{-1} \mathrm{~K}^{-1}\right]$