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Chemistry · 2021

JEE Main · 31 August 2021, Shift 2 · Q55

22 g of an organic acid is separately dissolved in 100 g of benzene ( K_b =2.6 K kg mol^-1) and 100 g of acetone ( K_b =1.7 K kg mol^-1). The acid is…

$\displaystyle 22$ g of an organic acid is separately dissolved in $\displaystyle 100$ g of benzene $\displaystyle \left(\mathrm{K}_{\mathrm{b}}=2.6 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)$ and $\displaystyle 100$ g of acetone $\displaystyle \left(\mathrm{K}_{\mathrm{b}}=1.7 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)$. The acid is known to dimerize in benzene but remain as a monomer in acetone. The boiling point of the solution in acetone increases by $\displaystyle 0.17^{\circ} \mathrm{C}$. The increase in boiling point of solution in benzene in $\displaystyle { }^{\circ} \mathrm{C}$ is $\displaystyle x \times 10^{-2}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest integer) [Atomic mass : $\displaystyle \mathrm{C}=12.0, \mathrm{H}=1.0, \mathrm{O}=16.0$ ]
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.