Chemistry · 2025
JEE Main · 22 January 2025, Shift 2 · Q71
20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is ____ × 10^-2 M. (Nearest integer)
$\displaystyle 20$ mL of $\displaystyle 2$ M NaOH solution is added to $\displaystyle 400$ mL of $\displaystyle 0.5$ M NaOH solution. The final concentration of the solution is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2} \mathrm{M}$. (Nearest integer)
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From NTA’s final answer key for this paper.
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.