Chemistry · 2024
JEE Main · 27 January 2024, Shift 2 · Q87
1 mole of PbS is oxidised by " X " moles of O_3 to get " Y " moles of O_2. X + Y = ____.
$\displaystyle 1$ mole of PbS is oxidised by " X " moles of $\displaystyle \mathrm{O}_3$ to get " Y " moles of $\displaystyle \mathrm{O}_2 . \mathrm{X}+\mathrm{Y}=$ $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
8
More from p-Block Elements (Groups 15 to 18)
- First ionisation enthalpy values of first four group 15 elements are given below. Choose the correct value for the element that is a main component…2025
- Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion A: H_2 Te is more acidic than H_2 S.…2024
- The strongest reducing agent among the following is:2024
- Regarding the hydrides of group 15 elements EH_3(E=N, P, As, Sb), select the correct statement from the following: A. The stability of hydrides…2026
- One mole of Cl_2( g) was passed into 2 L of cold 2 M KOH solution. After the reaction, the concentrations of Cl^-, ClO^- and OH^- are respectively…2026
- Given below are two statements: one is labelled as Assertion and the other is labelled as Reason (R). Assertion: There is a considerable increase in…2024
- Correct statements from the following are: A. Nitrogen in oxidation states from +1 to +4 disproportionates in acid medium. B. Nitrogen has the…2026
- The nature of oxide (TeO_2) and hydride (TeH_2) formed by Te, respectively are:2025
JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.