CBSE 2023 · Region 1 · Set 1 · Q22 · 2 marks
Two coherent monochromatic light beams of intensities I and $\displaystyle 4$ I superpose each other. Find the ratio of maximum and minimum intensities in the resulting beam.
Marking-scheme solution
\[\text { Finding the ratio of maximum and minimum intensities } 2
\]
\[\begin{aligned}
\frac{I_{\max }}{I_{\min }} & =\frac{\left(\sqrt{I_{1}}+\sqrt{I_{2}}\right)^{2}}{\left(\sqrt{I_{1}}-\sqrt{I_{2}}\right)^{2}} \\
& =\frac{I_{1}+I_{2}+2 \sqrt{I_{1}} I_{2}}{I_{1}+I_{2}-2 \sqrt{I_{1}} I_{2}} \\
& =\frac{5 I+4 I}{5 I-4 I} \\
& =\frac{9}{1}
\end{aligned}
\] Alternatively
\[\begin{aligned}
& \frac{I_{1}}{I_{2}}=\frac{a^{2}}{b^{2}}=\frac{4 I}{I}=\frac{4}{1} \\
& \frac{a}{b}=\frac{2}{1}
\end{aligned}
\]
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CBSE Class 12 Physics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.