CBSE 2023 · Region 1 · Set 2 · Q28 · 3 marks
The primary and the secondary coils of an ideal step-down transformer consist of $\displaystyle 650$ and $\displaystyle 25$ turns respectively. When the primary coil of this transformer is connected to $\displaystyle 240$ V mains, the current in the primary coil is $\displaystyle 1.5$ A . Calculate :(a)the voltage across the secondary coil(b)the current in the secondary coil(c)the average power delivered to the output circuit
The primary and the secondary coils of an ideal step-down transformer consist of $\displaystyle 650$ and $\displaystyle 25$ turns respectively. When the primary coil of this transformer is connected to $\displaystyle 240$ V mains, the current in the primary coil is $\displaystyle 1.5$ A . Calculate :
(a)
the voltage across the secondary coil
(b)
the current in the secondary coil
(c)
the average power delivered to the output circuit
Marking-scheme solution
\(\displaystyle \mathrm{N}_{\mathrm{p}}=650, \mathrm{~N}_{\mathrm{s}}=25, \mathrm{~V}_{\mathrm{p}}=240 \mathrm{~V}, \mathrm{I}_{\mathrm{p}}=1.5 \mathrm{~A}\)
(a)
\(\displaystyle \frac{V_{\mathrm{s}}}{V_{\mathrm{p}}}=\frac{\mathrm{N}_{\mathrm{s}}}{\mathrm{N}_{\mathrm{p}}}\)
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CBSE Class 12 Physics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.