CBSE 2025 · Region 4 · Set 2 · Q7 · 1 mark
The electric field in space between the plates of a parallel plate capacitor (each of area $\displaystyle 2.5 \times 10^{-3} \mathrm{~m}^{2}$ ) is changing at the rate of $\displaystyle 4 \times 10^{6} \mathrm{Vm}^{-1} \mathrm{~s}^{-1}$. The displacement current between the plates of the capacitor is :
Official answer
From CBSE’s own marking scheme for this paper.
(C)
$\displaystyle 8.85 \times 10^{-8} \mathrm{~A}$
Electromagnetic WavesDisplacement CurrentApplymcqmedium
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CBSE Class 12 Physics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.