Monochromatic light of wavelength 600 nm is incident from air on a water surface. The refractive index of water is 1.33. Find the (i) wavelength,…

Reflected high

$$\lambda^{\prime}=\lambda=$\displaystyle 600$ \mathrm{~nm} .

$$No change in wavelength

$$c=$\displaystyle 3$ \times $\displaystyle 10$^{$\displaystyle 8$} \mathrm{~m} / \mathrm{s} \text { in air }

$$$$ v=\frac{c}{\lambda}=\frac{$\displaystyle 3$ \times $\displaystyle 10$^{$\displaystyle 8$}}{$\displaystyle 5$ \times $\displaystyle 10$^{$\displaystyle 14$}} \mathrm{~Hz}

$$Refracted light

$$\begin{aligned} \lambda^{\prime}=\frac{\lambda}{\mu} & =\frac{600}{1.33}=$\displaystyle 451.1$ \mathrm{~nm} & \simeq $\displaystyle 450$ \mathrm{~nm} \end{aligned}

$$$$ \begin{aligned} v= & \frac{c}{\mu}=\frac{$\displaystyle 3$ \times $\displaystyle 10$^{$\displaystyle 8$}}{$\displaystyle 1.33$} & =$\displaystyle 2.26$ \times $\displaystyle 10$^{$\displaystyle 8$} \mathrm{~m} / \mathrm{s} & =$\displaystyle 5$ \times $\displaystyle 10$^{$\displaystyle 14$} \mathrm{~Hz} \end{aligned}