CBSE 2023 · Region 2 · Set 2 · Q19 · 2 marks
In a Young's double slit experiment, the separation between the two slits is d and distance of the screen from the slits is $\displaystyle 1000$ d . If the first minima falls at a distance $\displaystyle \mathrm{d}$ from the central maximum, obtain the relation between d and $\displaystyle \lambda$.
Marking-scheme solution
Obtaining relation between d & \(\displaystyle \lambda\)
$\displaystyle 2$
\(\displaystyle \mathrm{D}=1000 \mathrm{~d}\)
\[x_{1 \mathrm{d}}=\mathrm{d}
\] Position of \(\displaystyle 1^{\text {st }}\) minima.
\[\begin{aligned}
& x_{1 \mathrm{d}}=\frac{3}{2} \cdot \frac{\lambda \mathrm{D}}{\mathrm{d}} \\
& \mathrm{d}=\frac{3}{2} \cdot \frac{\lambda \times 1000 \mathrm{d}}{\mathrm{d}} \\
& \therefore \quad \mathrm{d}=1500 \lambda
\end{aligned}
\]Wave OpticsInterference of Light Waves and Young’s ExperimentApplyvery_short_answermedium
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CBSE Class 12 Physics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.